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JQL filter issues by Parent Status

Hello,

 

I need a filter that I can use which shows all the issues that belong to a project and in which the parent status != Done.

 

Something like this one... but having the status filter limited only to the parent (not all the issues):

project = myProject AND status != Done AND Sprint in openSprints() ORDER BY key ASC, parent ASC, Rank ASC

 

Basically: only hide anything with a parent status = Done... and show all else.

Even issues in Done should be shown as long as their parent's not in Done status.

 

Thanks!

Federico.

1 answer

1 vote
Mark Segall
Community Leader
Community Leader
Community Leaders are connectors, ambassadors, and mentors. On the online community, they serve as thought leaders, product experts, and moderators.
Mar 30, 2023

Hi @Federico Varchavsky - Unfortunately, you cannot get something like this with native JQL.  There are marketplace apps that provide JQL extensions which would be able to provide this capability.

Nooooooo!

This is terrible for my organization... both personal and corporate organization. hehehe.

 

Is there any way to concatenate different filters?

 

Like having a filter which only show the US i need... and in another filter having all the issues the belong to that filter I just created.

Something like:

 

myUSFilter = shows all the US that I need to find

myIssuesFilter = show me all the issues which IN myUSFilter

 

Thanks Mark!

Mark Segall
Community Leader
Community Leader
Community Leaders are connectors, ambassadors, and mentors. On the online community, they serve as thought leaders, product experts, and moderators.
Mar 30, 2023

Unfortunately not.  You're looking for the ability to establish subqueries which native JQL just isn't advanced enough to handle on its own.

:( Thanks @Mark Segall  for your prompt response!

Like Mark Segall likes this

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