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How can I output the release dates of multiple Fix Versions in order in a Custom Field? Edited

Jordan Klein Nov 27, 2017

The code below (courtesy of @Joshua Yamdogo) assigns the release date of a Fix Version to a custom field, assuming the issue has one Fix Version.

enableCache = {-> false}
def version = issue.getFixVersions()
version.first().getReleaseDate().format("dd/MMM/yyy")

 

I would like the Release Date field to update as a multi-line text field that accounts for the possibility of multiple Fix Versions.

 

If there was one Fix Version, Milestone 12, it would say:

Release Date: 11/27/17 (Milestone 12)

 

If there were multiple Fix Versions, Milestone 12-14, it would order all of them by release date:

Release Date: 11/27/17 (Milestone 12)

                       12/4/17 (Milestone 13)

                       12/11/17 (Milestone 14)

 

Could you help me regarding how to check for an increasing number of Fix Versions and then order based on their respective release dates?

 

This is what I've got so far

enableCache = {-> false}
def version = issue.getFixVersions()
def numFixVersions = version.size()
def versionDates = []
def i = 0

for (i; i < numFixVersions; i++) {
versionDates.add(version[i].getReleaseDate())
}

versionDates.sort()

for(i=0; i < numFixVersions; i++){

versionDates[i].format("dd/MMM/yyy")

}

 

The format() function is working for issue.getFixVersions().getReleaseDate() but not for my versionDates array that should be comprised of the same release dates.

3 answers

0 votes
Jordan Klein Nov 27, 2017 • edited

(Accidental comment)

0 votes
Marthe Ngo Temb Mar 25, 2018

Hi Jordan,

Please I wanted to know if you could find a solution in case there are more than one Fix Version?

Thank you

0 votes
Casey Maynard Apr 03, 2019

What is the process of where I should create this 'code'?

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