I would like to create a filter that will return the following results:
Issue Type: Sub-task
Issue Type of Parent Task: XYZ
Using the JQL Tricks Plugin (or OOTB JIRA capabilities), is there a way to accomplish this?
My apologies. I should have added that I've tried this, but am getting an error at character 67, which I'm assuming is related to my use of quotes:
project = "Client Services Projects" AND parent in ("issuetype = "MRC Task"")
Unfortunately, any combination of quotes that I try are giving me:
Error in the JQL Query: Expecting ',' or ')' but got 'MRC'
Getting closer! When I try that, I get the following error:
The issue key 'issuetype = MRC Task' for field 'parent' is invalid.
I've also tried the query with an issue type of Task (which is a valid issue type for the project) and got the same error (but with 'Task' instead of 'MRC Task' in the error).
Is there a way to get exactly the same result but with a variable and a comparison? To be precise:
For a specific issue type we want to have only the sub-tasks of this specific issue type and no others.
So a query could look like this:
issue in parent ("issuetype = 'valueofcustomfield'") and customfield = Meeting XY
Where Meeting XY is supposed to be equal to the valueofcustomfield to be shown. The subtask did inherit the the value of the issuetype to the customfield before from the parent.
I hope this was understandable
Thanks for any advice!
I use the free app JQL Booster with this syntax to solve this issue.
Ok, the problem is with an add-on is many people work in a company that does NOT allow users to download or install add-ons without a huge issue and at least 6 months of red tape. Oh and if you can't justify it as saving a significant amount of money then you can't get your request high enough in the queue to ever be reviewed.
Typed on a small screen so forgive the spelling and grammar
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