You're on your way to the next level! Join the Kudos program to earn points and save your progress.
Level 1: Seed
25 / 150 points
Next: Root
1 badge earned
Challenges come and go, but your rewards stay with you. Do more to earn more!
What goes around comes around! Share the love by gifting kudos to your peers.
Keep earning points to reach the top of the leaderboard. It resets every quarter so you always have a chance!
Join now to unlock these features and more
The Atlassian Community can help you and your team get more value out of Atlassian products and practices.
I've created a couple of quick filters (in the Kanban board settings). All are working correctly in the advanced search, but one of them is not working as a quick filter. The only difference I can find between them is that the fault filter has a weird-looking user id.
Working example:
reporter = 62401a71f3824d006a124edd
Not working:
reporter = 712020:85888e4e-0be6-4809-95a9-b40115603785
Any idea?
Thanks!
Hi @Gil Alroy and welcome to the community,
The second JQL doesn't really seems like an account id. It could be an old account id, but it surely resemblance a group id. Question: if you go to advanced search, type
reporter = 712020:85888e4e-0be6-4809-95a9-b40115603785
and then switch it back to basic sql, what does it say? Which field is selected? Can you post a screenshot of it?
Thanks! The JQL identifies the user but not the quick filter.
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
@Gil Alroy found the answer here https://community.developer.atlassian.com/t/account-id-formats/41061
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.