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JMCF - How to Compare a Selected List Value with a String

Jacob Clouse

I have a custom field that is a Calculated Number Field. I am trying to compare the selected value of a Select List (single choice) field with a string. However, my comparison always returns false even when the selected value matches the string being compared with.

In the formula below, the return value is always 0 (unless the field is null, then it's -1).

The field value is "3-Moderate" but when I compare the field value using issue.get with "3-Moderate" it returns false. I have also tried adding toString() after issue.get() and that does not work either.

Calculated Number Field Formula

@Formula:
var severity = issue.get("customfield_11600");
log.error("value of severity is " + severity);
var moderate = "3-Moderate";
log.error("value of moderate is " + moderate);
(severity != null ? ((severity == moderate) ? 1 : 0) : -1)
--&gt;

JIRA Debug Log

2016-10-28 13:21:13,056 http-bio-8080-exec-43 ERROR username 801x81376x2 1p9ubvx ip.address.hidden /secure/AjaxIssueEditAction!default.jspa [innovalog.jmcf.fields.CalculatedNumberField] value of severity is 3-Moderate
2016-10-28 13:21:13,056 http-bio-8080-exec-43 ERROR username 801x81376x2 1p9ubvx ip.address.hidden /secure/AjaxIssueEditAction!default.jspa [innovalog.jmcf.fields.CalculatedNumberField] value of moderate is 3-Moderate

JIRA version v6.3.15 and JMCF version 1.7.1.

Accepted answers

David _old account_

You should not be using JMCF 1.7.x on JIRA 6.3. JMCF 1.7.x is for JIRA 7 and above.

As for your formula, you should compare strings using the equals() method:

@Formula:
var severity = issue.get("customfield_11600");
log.error("value of severity is " + severity);
var moderate = "3-Moderate";
log.error("value of moderate is " + moderate);
(severity != null ? ((severity.equals(moderate)) ? 1 : 0) : -1)
--&gt;

All comments

David _old account_

You should not be using JMCF 1.7.x on JIRA 6.3. JMCF 1.7.x is for JIRA 7 and above.

As for your formula, you should compare strings using the equals() method:

@Formula:
var severity = issue.get("customfield_11600");
log.error("value of severity is " + severity);
var moderate = "3-Moderate";
log.error("value of moderate is " + moderate);
(severity != null ? ((severity.equals(moderate)) ? 1 : 0) : -1)
--&gt;

Jacob Clouse

Thank you, @David [Innovalog].

The severity.equals(moderate) resolved my issue. I've also put in a request to have our local JIRA instance upgraded to the latest version.

James Webber

@David [Innovalog]

This is great - Thanks heaps

I have an extension question if its okay.

I ideally want to compare and assign a value based on a combination of two values Consequence and Likelihood. SO I have tried this. Assigning a var to each field.

Creating a var for the values they can equal. But I can't get the second condition to fire. I.e I can get it to work if likelihood = Possible and Consequence = Minimal but if the value = Moderate it doesn't work. If I switch them it works for the frist but not the other. Any idea how I can get a number of conditions to check like this?

It seems I can only compare one condition at a time?

@Formula:
var Likelihood = issue.get("customfield_10102");
var Consequence = issue.get("customfield_10101");
var Minimal = "Minimal";
var Moderate = "Moderate";
var Possible = "Possible";
((Consequence.equals(Minimal))||(Likelihood.equals(Possible))? "MinPos": null))

((Consequence.equals(Moderate))||(Likelihood.equals(Possible))? "ModPos";0))
-->

James Webber

Sorry should mention I had picked up the semi colon and its not that.

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