the Following query is not returning the values
project in("Project 1","Project 2") AND assignee in (User 1,User 2,User 3.User 14) AND issue in ("Issue 120","Issue 220")
Hi True,
Try using key instead of issue in that last part, assuming issue1 and issue 2 are in the format of ABC-123, ABC-456
Hi @True Indian , thanks for your post.
Wouldn't you achieve the same thing just querying?
issue in (key-1, key-2)
It doesn't really add value to also specify the assignee, anyway you can't have 4 assignees for 2 work items.
Please can you clarify what you are trying to achieve?
Best wishes
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