All, i have s tructure board that inludes
1. Themes
1.1 Products (Themes)
1.11 Requests
1.111 Technical Implementation (requests)
These levels are all linked as "is child of" links. I would like to add an attribute to my structure that shows the Fix version of all linked / child requests so for level 1 all underneath) for level 1.1 all underneath etc. Would you be able to provide the code / for the formula to be added to my structure? Many thanks
Hello @Michael Kocher
You can show all assigned versions in the branch with a formula like this:
array{versions}.flatten()
Alternatively, you can exclude own versions of parents with a modifier if you want:
array#strict{versions}.flatten()
I hope this helps. If you need further assistance, please reach out to us directly through our support portal.
Best regards,
Stepan Kholodov
Tempo
This is exactly what I need. Many thanks One last question: Is there a chance to exclude duplications?
At the moment:
- Product (Release 1, Release 1, Release2)
-- Item (Release 1)
-- Item (Release 1)
-- Item (Release 2)
--> For the product, it would be nice if there the array#strict would only show Release 1 once, to avoid duplication?!
KR
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Just add .unique() to the end of the formula.
Best regards,
Stepan Kholodov
Tempo
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