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Quickfilter JQL Query for Assigned Tester?

Traci Kowalkowski
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August 23, 2024

I have clients that complete testing on different tickets. When they select a ticket to test, they put themselves into the tester field of the ticket. I would like to be able to filter the tickets that a particular client is the tester for. Any ideas of a JQL query that would do this?

2 answers

2 votes
Trudy Claspill
Community Champion
August 23, 2024

Hello @Traci Kowalkowski 

Welcome to the Atlassian community.

What type of field is the "tester" field? Is it a user picker, a selection list, or something else?

With just native functionality you can create explicit Quick Filters using JQL. You would have to create one Quick Filter for each possible value of the tester field.

Traci Kowalkowski
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I'm New Here
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August 26, 2024

The tester field is a selection list of all the people assigned to the project (developers, clients, QA tester et al.) I know I would need a Quick Filter for each possible value. I am looking for the JQL query to use to filter those values.  For example, in the image below, I've assigned myself as tester on this ticket. I would like to now filter all tickets to those that only have user "Traci" as the Tester.  Is that possible?

Screenshot 2024-08-26 094715.png

Trudy Claspill
Community Champion
August 26, 2024

Hello @Traci Kowalkowski 

If you are new to creating filters you might benefit from the free training available from Atlassian University.

https://university.atlassian.com/student/catalog/list?search=jql

There is also the documentation on performing basic searches, and then transitioning into JQL searches.

https://support.atlassian.com/jira-software-cloud/docs/search-for-issues-in-jira/

A JQL statement is comprised of fields with criteria operators and values, with those being combined using AND and OR to make more complex statements. For a simple filter like yours the statement would be

"Tester"=insert value

Use the View All Issues screen (under the Filters menu) to work out the JQL and make sure you are getting the results you expect. Then copy that to a Quick Filter in your board.

0 votes
shiva kumar Gosul
Contributor
August 24, 2024

Type Assignee=employee id

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