I have a JIRA filter and I would like to open all the JIRA tickets automatically without doing it manually present under the filter daily at certain time.
This is what my approach is:
Added a Trigger:
After this I am trying to add appropriate action to open all the child tickets under the JQL but not able to figure out the right action.
Can someone help me with this.
Hi @Mayank Rawat , welcome to the Atlassian Community and thanks for your post.
Can we back up a step please, you want to create, every day, a series of tickets under a parent?
Can I ask why please?
The JQL for this should be relatively simple, in that case, you should be able to write, Parent in (key-1). I always recommend people to use the Automation library to find an example rule and modify that, like these - https://www.atlassian.com/software/jira/automation-template-library/rules#/rule-list?systemLabelId=all&filterText=sub&page=1&pageSize=20&sortKey=name&sortOrder=ASC
Please have a look at these and share your feedback.
Best wishes
Can you please try this once
Trigger that is scheduled: Choose "Scheduled" and choose a frequency of 9 AM IST every day.
Action for lookup issues: Enter your filter in "Lookup Issues" as a JQL.
Branch rule and associated problems (JQL): To make the rule iterate through every ticket in the lookup, add a branch for JQL and use the same filter JQL.
Action on the transition issue (inside the branch): Choose the "Transition issue" action and set the status to "Open" (or the corresponding workflow value).
Hope this helps.
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