Can Sub-tasks be added to a sprint individually?

[Hitesh]

Hello,

I have multiple issue which contain around 13-14 sub-tasks linked to them. I know for a fact that when we add a parent task into a sprint the child will get tagged with the same sprint. But i wanted to know if there is a way to have these sub-tasks be added into a sprints individually.

My use case: Lets say along with the parent task only 4-5 sub-tasks can go into first sprint we want to add the rest to another one.

Please advice.

Thanks!!

[Trudy Claspill]

Hello @Hitesh 

No, subtasks cannot be added to a Sprint independently from their parent issue.

With the scrum methodology the idea is that a task/story is scoped such that it can be completed within a single sprint. And subtasks describe the work required to complete that parent issue.

If the task is too large to be completed within a sprint then it should be split into two tasks; each of which can be completed within a sprint. 

Otherwise you will have to add the parent task to one Sprint, complete as many of the subtasks as you can, and then roll the task into another sprint during which you can complete the remaining subtasks.

[Pasam Venkateshwarrao]

Hi @Hitesh 

You can't do this at all.  Sub-tasks are part of their parent, and hence not even considered to be part of a sprint.  They go with their stories into a sprint, all together because they are a part of their parent.

The concept of having sub-tasks in different sprints is simply wrong.  The parent goes into a sprint and, because the sub-tasks are part of it, they go with it.

If you are regularly finding you are partially completing a story and hence rolling it into the next sprint (with its component sub-tasks), then you either need to improve your estimates and sprint selection, so that you don't commit to too much work, or improve your story writing, breaking up your stories more, so that you can commit to the right amount of work by only taking in what you can do.

[David Bakkers]

That is just a duplication of the same answer that @Trudy Claspill provided, 3 hours ago