How to display a field depending upon other field.

[ab185178]

I am trying to display a Label type field only on the condition that the Issue type is Inspection Defect. This is the code that I am using:

<script type="text/javascript">
issuetype = document.getElementByName('issuetype');
if (issuetype)
{ target = document.getElementById('customfield_11200'); // Hide the target field if issuetype not Inspection Defect
if (issuetype.value != 7)
{ target.style.display='none';
}
else
{ target.style.display='inline';
}
}
</script>

Please let me know if I need to change anything.

[Pascal Collard · Accepted solution]

Hi;
Are you sure getElementByName is compatible with the browser? It's not a native function for all browsers.
Maybe ujse jQuery to be more cross-browser compatible? Will be easier for you to hide/show the element too.

[Jobin Kuruvilla [Adaptavist]]

In JIRA 4.4, you can do something like this:

<script type="text/javascript">
if (AJS.$("input[name=issuetype]").val() != 1){
 AJS.$(".aui-field-labelpicker").hide();
}
</script>