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Suggestions how to configure a JPD expression in a custom formula field to display 2 decimal places?

Michael Tucker
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May 20, 2026

Our organization is new to Jira Product Discovery and we're using it as an intake form to help with ideation and prioritization. I have created several weighted fields whose values are 1, 3, and 5 with those respective weightings. I have successfully created a custom formula field expression that applies different weightings, but it's rounding only to the tenth decimal place and I need the hundreth decimal place (for instance, the formula is producing 1.9 when I need 1.87). That expression is: 

(({Revenue - EVA Impact}*0.4)/4)+(({Revenue - Contract Volume}*0.4)/4)+(({Revenue - Strategic Alignment}*0.4)/4)+(({Revenue - Time to Value}*0.4)/4)+(({Cost Savings - Expected Cost Reduction}*0.35)/3)+(({Cost Savings - Risk & Compliance Avoidance}*0.35)/3)+(({Cost Savings - Efficiency Gain}*0.35)/3)+(({Engineering - Effort Size}*0.25)/2)+(({Engineering - Enablement Value}*0.25)/2)

There are Revenue, Cost Savings, and Engineering categories whose weights are 40%, 35%, and 25% respectively. 

I have tried using Rovo to help and the suggestion is to implement ROUND(my_expression, 2)

I have tried repeatedly with different variations of that, but am always receiving a "Could not parse expression" error. 

Any guidance on how I can change that expression to get the hundreth decimal place? 

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