How to Configure an Assets Custom Field to Display a Manager Based on Employee Selection

Question

I currently have one custom field where I select an employee by displayname, such as "Tom," and I need another new custom field to display Tom's manager, "Amy." Specifically, the new field should be able to select "Amy" with the object ID ORG-2.

Here is my Assets data:

LTW_Employee

Object IDobjectTypedisplaynameManagerORG-1LTW_EmployeeTomAmy (ORG-2)ORG-2LTW_EmployeeAmyBob

The first field is an "Assets objects" custom field that allows me to choose an employee (e.g., ORG-1 for "Tom").

The Manager attribute is a linked object, pointing to another LTW_Employee (e.g., ORG-1 links to ORG-2 for "Amy").

The second field should dynamically show the manager (e.g., "Amy" from ORG-2) based on the first field’s selection.

I tried configuring the second field with the following AQL in the Filter Issue Scope:key = ${customfield_12345.Manager}

(where customfield_12345 is the ID of the first field), but I got an error: "The AQL query contains one or more placeholder values that are invalid or incorrectly formatted."

How can I achieve this? Is there a correct AQL syntax to reference the Manager attribute of the first field’s selected object? Or do I need to use Automation for Jira to make this work? Any help or examples would be appreciated!

Calvin · Answer

Apologies, turns out I'm reading this the wrong way, so removing the comment. The only way I know how to do via the filter scope itself is by using the inbound or outbound reference.

eg:

object HAVING inR(objectId IN ($custom_field_xxxxx${0}}), refType IN ("Reports to"))

Changing Report to, to manager to or however reference type you have setup for that object.

LogicalisTW · Answer

Calvin · Answer

Hi, my guess is in the second custom field is also an asset one? As such you want to return the "object" not "key"?

Maybe try:

object = ${customerfield_1234.Manager}