Distinct user from multi-user custom field in Jira Automation

Question

Hi all,

I am creating an automation that will send emails to all interested users when a version is released. There is a custom issue field "Notify on Release" that can contain multiple users per issue who should be notified.

I fetched all issues where this custom field is not empty and now need to get a list of distinct users to be notified. If my custom field contained only a single user, I could simply assign this to a new variable: `{{lookupIssues.Notify on Release.distinct}}`, but since my custom field can contain multiple users this will not work.

Example:

* Issue 1 - Notify on Release: User A, User B
* Issue 2 - Notify on Release: User A
* Issue 3 - Notify on Release: User A

This would result in the following list: (User A, User B) , User A.

Is there a way to combine all elements in a single list first and then run distinct on them?

Thank you in advance!

Cornelius Schiffer · Answer

Hi Alex,

thank you for the answer!

I tried it like this:

The first log shows the users, the second only the static text. My new variable "distinctUsersToNotify" seems to be empty.

Alex Koxaras -Relational- · Answer

Hi @Cornelius Schiffer

Can you try to create a new variable after that lookupissues and assign the value of {{lookupIssues.Notify on Release.distinct}}. Then call the distinct method on the new variable. Log it and see what this yields.