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How can a Confluence User Download all Attachments in a Space?

How can a Confluence User Download all Attachments in a Space?

Each client project is in a space and when the project is over, we need to be able to have them download the attachments without going page by page. The Pages we can export to one PDF file but no solution for attachments.

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I will just add that if you want the files to be separately as files you can do that and ensure they have descriptive names. (and not face a problem with PDF export with certain types of attachments due to embed) there is another way.

Space tools > Content Tools
Find the Export tab
xml export (this gives us neat xml file with id mapped to name)
. Do a HTML export (this gives us files named with IDs to match the ID in above xml file)
Then I ran python script to simply rename the attachments so can be easily identified. (I am taking no responsibility for the code below not working or working improperly on end machine):

import os
import xml.etree.ElementTree as ET

# Path to the directory where the files are saved
directory_path = r"path\to\html\export\attachments\folder"

# Path to the XML file
xml_file_path = r"path\to\file.xml"

# Parse the XML file
tree = ET.parse(xml_file_path)
root = tree.getroot()

# Create a dictionary to store file IDs and real names
file_dict = {}

# Extract file IDs and real names from the XML
for attachment in root.iter('object'):
attachment_class = attachment.attrib.get("class")
if attachment_class == "Attachment":
file_id = attachment.find("./id[@name='id']").text
real_name = attachment.find("./property[@name='title']").text
file_dict[file_id] = real_name

# Rename files in place
for root_folder, _, files in os.walk(directory_path):
# Create a dictionary to track counts of each file name in a directory
 name_count = {}

for filename in files:
file_id, file_extension = os.path.splitext(filename)

# Check if the file ID exists in the dictionary
 if file_id in file_dict:
real_name = file_dict[file_id]
base_name, ext = os.path.splitext(real_name)

# Check if the file name already exists in the directory
 if base_name in name_count:
name_count[base_name] += 1
 new_base_name = f"{base_name}_{name_count[base_name]}"
 else:
new_base_name = base_name

name_count.setdefault(base_name, 1)

new_name = f"{new_base_name}{ext}"
 old_path = os.path.join(root_folder, filename)
new_path = os.path.join(root_folder, new_name)

# Rename the file
 os.rename(old_path, new_path)
print(f"Renamed: {old_path} -> {new_path}")