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Hide Transition based on the presence of Linked Issues

Edited

Hello Team,

I have a transition (Create a Defect) at two Statuses called 'Step 1' and 'Step 2' in the workflow.

At Step 1, When I click on Create a Defect, a linked issue gets created. 

When I reach the Step 2 status, I should not see "Create a Defect" transition as I already have a linked issue present in the ticket.

I wanted to hide/unhide the transition based on the presence of linked issue in the current issue.

 

We use JWT, ScriptRunner plug-ins.

 

Please help me in this regard.

 

Regards,

Sriharsha

1 answer

1 accepted

0 votes
Answer accepted
Tansu Akdeniz Community Leader Jul 28, 2022

Hi @Sriharsha 

Welcome to the community.

You can add a simple script condition via Script Runner. There are sample scripts in that page. For ex; linked issue condition: 

!issueLinkManager.getOutwardLinks(issue.getId())*.issueLinkType.name.contains('Relates')

Or you can add JQL condition by using issueFunction not in hasLinks() query.

Best

You're welcome!! 

Hello @Tansu Akdeniz , 

hope you are doing well!

It is working as expected.

But I have another scenario in the same workflow, where at a later status, when I click a transition button in the ticket, it goes back to the previous status and again I can see "Create A Defect" button.

Once a linked issue is created, I should not see no matter how many times I come back to the previous status.

Can you pls suggest?

 

Thank you!

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