Hi guys
I have a question regarding JQL statements.
I have a Kanban Board which should display all Stories that are related to Epics with a specific fixVersion.
Example:
In this situation, my filter behind the board should display the stories related to epics with fixVersion 2404. This would mean, I should be able to see Story aa, Story ab and Story ca.
How can I build a JQL statement, that filters for a specific project and AgileObjects and fixVersion and includes all childissues EVEN if they do not have neither the AgileObjects nor the fixVersion.
I hope I was able to explain that understandable.
Thank you for your support
welcome to the community!
Unfortunately, this is trickier than one might think; as a hierarchical query, it would really require some kind of join or subquery, which isn't available in plain Jira/JQL.
A few directions forward:
If you want to run your search dynamically, without manually stitching two queries together, you'll need extra tooling:
Hope this helps,
Best,
Hannes
Just to expand on the last point, this is how this would look in the app that my team and I are working on, JXL for Jira. Put simply, you'd create a sheet with all issues that are potentially relevant to you, enable the default issue hierarchy (that's just one click), and then use JXL filtering capabilities to narrow down to the issues that you care about:
(I'm using labels here, but it would work the same way with any other field.)
Once you have your list of issues, you can work on these directly in JXL (much like you'd do in e.g. Excel or Google Sheets), trigger various operations in Jira, or export them for further processing.
Any questions just let me know!
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Hi @Hannes Obweger - JXL for Jira
Thank you for your response.
I could go with the first option, which would mean some manual work every PI but would be better than have to add fixVersions to every Story.
The automation would be nice as well but as far as I understand, automations can slow down the project quite a bit if there is a lot of load on it already. Do you know more about that?
Another app is probably not possible for me.
Kind regards
Karin
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