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Cron expression for quater

Urszula Forenc

Hi,

how can I write a cron expression for:

Every first day of a quater ?

The purpose is to create an Automation rule, where issues older than 3 years must be deleted, sheduled every first day of a quater (1 Jan, 1 Apr, 1 Jul, 1 Oct). It also need to send email, that this deletion will ocurre (one week before the deletion).

Thank you!

Accepted answers

tomd_2ll1qh

Hello Urszula,

A crontab entry for the first day of every quarter:

0 0 1 */3 *

source: https://crontab.guru/every-quarter

Tom

All comments

tomd_2ll1qh

Hello Urszula,

A crontab entry for the first day of every quarter:

0 0 1 */3 *

source: https://crontab.guru/every-quarter

Tom

Urszula Forenc

Hi, it doesn't work...

Urszula

Urszula Forenc

Ok, it needs "?" on the end of the crone expression - that means, that the day of week (Mon, Tue...) doesn't matter.

Rosa M Fossi

@Urszula Forenc Hi Urszula! Did that expression work?

I'm also using Automation for JIRA... but the expression above seems to be missing a leading "0" (since per JIRA documentation, the seconds part of the string is required).

I'm building a quarterly automation, and this is what I've come up with....

0 0 0 15 */3 ?

which in theory should next run July 15th 2019.

Let me know if the extra zero wasn't necessary! Thanks

Urszula Forenc

Hi Rosa,

I use it: 0 0 1 */3 * ?

I've found very usefull website: cronmaker.com - you can test there your crones.

Urszula

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