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Parent child issues

Ganesh_6lvvfv

HI Community!!!

I m able to move child issues dynamically when parent is moved !!!

Ex: I m moving parent from (TODO to INPROGRESS & INPROGRESS to TODO) so child issues are behaving the same (TODO to INPROGRESS & INPROGRESS to TODO)!! to achieve this I have used this postop(

Transition related issues (JMWE app)

Transition all related issues (such as linked issues, Stories of an Epic, Epic of a Story, subtasks of an issue, issues returned by a Groovy script or a JQL search, etc.)

)

However I need to put child issues to be constant when child issues moved to DONE Status!!!!

for above scenario child issue is moving (irrespective of any status) accordingly when parent is moved!!!

Can someone help me with some groovy script or any condition do I need to apply to accomplish this!!!

Thanks in advance!!!

Accepted answers

Sayed Bares {Appfire}

Hi Ganesh,

Hope you are doing well.

To achieve your use case you just need to enable Conditional execution parameter in Transition related issues (JMWE app) post-function and add the following code:

linkedIssue.get("status")?.name != "Done"

Hope it helps and let us know how it goes.

Best,

Sayed

All comments

Sayed Bares {Appfire}

Hi Ganesh,

Hope you are doing well.

To achieve your use case you just need to enable Conditional execution parameter in Transition related issues (JMWE app) post-function and add the following code:

linkedIssue.get("status")?.name != "Done"

Hope it helps and let us know how it goes.

Best,

Sayed

Ganesh_6lvvfv

@Sayed Bares {Appfire} I m good thanks!!!

Hope you are doing good!!

The answer you are suggested working absolutely fine!!!

However I tried to add multiple statuses to it like below

linkedIssue.get("status")?.name != "Done","Inreview","Accepted"

It is throwing me error!!!

Could you please suggest where am doing wrong adding multiple statuses!!! Thanks in advance!!!

Sayed Bares {Appfire}

Hi @Ganesh

I am doing great thanks for asking.

To skip multiple statuses you can use the following code:

!(linkedIssue.get("status")?.name in ["Done","Inreview","Accepted"])

The reason the code you have used before didn't work is because != operator can only work with one status not multiple. But with the above, you should be able to achieve what you are trying to do.

Hope it helps and let us know how it goes.

Best,

Sayed

Ganesh_6lvvfv

@Sayed Bares {Appfire} Thank you for taking your time to writing to me!!

I have tried the above code , however it is not working my cases!!!

Child in Inreview status !!! I moved parent to todo/Inprogress so it is moving back child to the same status(i,e todo/Inprogress) same case with Accepted and done!!!

Could you please suggest me some other code or modifications!!

Note: I have tried "!" and "!=" begining of the code!!! But has no luck!!! Thanks!!

Regards,

Ganesh!

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