how to see the details of "The remote server returned an error: (400) Bad Request." in C#

Question

how to see the details of "The remote server returned an error: (400) Bad Request." in C#?

I can only see the 400 Bad Request. it didn't see anything more.  not like curl command line.

Anshul Yadav_vcydna · Answer

how to resolve to same problem that The remote server returned an error: (400) Bad Request. please suggest me please

using (var client = new WebClient())
{
client.Headers.Add("Content-Type", "application/json");
client.Headers.Add("Accept", "application/json");
client.Headers.Add("Authorization", "Bearer " + zoomaccesstoken);
client.Headers.Add("Cookie", "TS018dd1ba=0135c3e7ce5af3c1d80c8393d3120501505b8aadaca541beb2e6d62b1f1da9b1441b760b42bf222ddd1493fee22214af1420d169d9; __cf_bm=C2EMhl36Jhy4brGh7fyNUEeopvY.IlkwBQ2giNgFLmM-1687411236-0-ATNLVGTGqXEhNj277g/f/YPcO9CKi0Vy4wZhOoyCjd0zFzc/UTi7Mb5F8Js4e1NI61Lt8qyCslwqtfsja7CUa3w=; _zm_bu=https%3A%2F%2Fzoom.us%2Foauth%2Fauthorize%3Fclient_id%3Du43I1TYkQFiSJsa8zv2Rrg%26response_type%3Dcode%26redirect_uri%3Dhttps%253A%252F%252Fllama.chipsoftindia.com%252Fevents; _zm_chtaid=227; _zm_csp_script_nonce=3bKSprXfRt-w43ms6EIKtg; _zm_ctaid=rUdyvPO5RBWjBY6DUrAhng.1687411621553.c30f0b05e5d4e06c7ba6d1d8f9a7df0b; _zm_currency=INR; _zm_mtk_guid=1ac74555fe124cba86040a3823958b17; _zm_o2nd=e2cf1797f4054b67a7ba12eef8bf61e3; _zm_page_auth=us06_c__QD3j4hgRpGjzq4hErlwLg; _zm_ssid=us06_c_L-GD3UBuQIC8UtHjjtVl9A; _zm_visitor_guid=1ac74555fe124cba86040a3823958b17; TS01f92dc5=0135c3e7ce5af3c1d80c8393d3120501505b8aadaca541beb2e6d62b1f1da9b1441b760b42bf222ddd1493fee22214af1420d169d9; cred=9ABFCDDEC25356B8ED9F76D6F0901190");

var url = "https://api.zoom.us/v2/users/me/meetings";
var body = @{
""pre_schedule"": false,
""start_time"": """ + timeFromUTC + @""",
""timezone"": ""UTC"",
""topic"": """ + topic + @""",
""type"": 2
}";

var response = client.UploadString(url, "POST", body);

ZoomCreateMeeting objCM = Newtonsoft.Json.JsonConvert.DeserializeObject<ZoomCreateMeeting>(response);
return objCM;
}

Andy Kuan · Answer

thanks

Warren_mz9b4z · Answer

Hi @Andy Kuan

I use something like this

try
{
HttpWebResponse response = newRequest.GetResponse() as HttpWebResponse;
}
catch (WebException we)
{
Stream stream = we.Response.GetResponseStream();
StreamReader sr = new StreamReader(stream);
string strMessage = sr.ReadToEnd();
}

where strMessage in the catch area has the details of the error