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Condition to hide "Created Linked issue"

zaharovvv_suek_ru

I have a condition to hide "Created Linked issue" if issue is:
- project of key is "LO"
- type of issue is "Epic"
- status of issue is "Closed"

So I write the following query:

jiraHelper.project?.key != "LO" &&
 issue?.issueType?.name != 'Epic' &&
 issue?.getStatus()?.getName() != 'Closed'

and the above query hides "Created Linked issue" in issue types such as "New Feature", "Epic":

I've tried to change the query:


jiraHelper.project?.key == "LO" &&
 issue?.issueType?.name == 'Epic' &&
 issue?.getStatus()?.getName() != 'Closed'

However, it again hides "Created Linked issue" in issue types such as "New Feature", "Epic".

How can I hide "Created Linked issue" if issue is:
- project of key is "LO"
- type of issue is "Epic"
- status of issue is "Closed"
?

Accepted answers

Tarun Sapra

Hello @zaharovvv_suek_ru

!(jiraHelper.project?.key == "LO" &&
 issue?.issueType?.name == 'Epic' &&
 issue?.getStatus()?.getName() == 'Closed')

Above code means *NOT* of

- project of key is "LO"
- type of issue is "Epic"
- status of issue is "Closed"

All comments

Neta Elyakim

If you want to limit the link issue function just for one status in one workflow- a better solution will be to put on the status properties :

jira.permission.link.denied

It's work.

You can just go to you relevant workflow-> open as a diagram -> click on the status -> click Properties -> then add "jira.permission.link.denied" under Property Key -> add -> publish workflow.

Tarun Sapra

Hello @zaharovvv_suek_ru

!(jiraHelper.project?.key == "LO" &&
 issue?.issueType?.name == 'Epic' &&
 issue?.getStatus()?.getName() == 'Closed')

Above code means *NOT* of

- project of key is "LO"
- type of issue is "Epic"
- status of issue is "Closed"

Tarun Sapra

You can put this in the condition in the web fragment

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