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How to zip a dir in pipeline step

unknown

I have a number of files being generated from my build which I want to publish together in a single zip file. I tried scripting this making use of the 'zip' command, however I get the following error. Is this possible?

<span>bash: zip: command not found</span>

<span> </span>

Accepted answers

All comments

Ana Retamal

Hi Jon, can you show us your bitbucket-pipelines.yml file? Can you confirm you have 'zip' installed?

Regards!

Ana

Stephan Hradek

Hi Ana,

I also want to zip in a pipeline and I also come across the error

bash: zip: command not found

Could you please assist: How could I get zip installed (in a pipeline) so that I can use it?

Stephan Hradek

I'm using this workaraound now:

Instead of

- zipfile="filename"
- dir="directory"
- zip -r $zipfile.zip $dir

I'm using pythons like so:

- zipfile="filename"
- dir="directory"
- python -c "import shutil;shutil.make_archive('$zipfile','zip',root_dir='.', base_dir='$dir')"

This will create a zipfile without having to install zip

Vimal krishnamoorthy

I want to do the same thing . Want to zip the files in the repository using bitbucket pipeline yml file

Please anyone , guide me ?

Asim AlTwaijri

add this command to your scripts:

- apt-get install zip

Vicente Amorós Aldea

Thank you ! you saved my day

Pedro Guerrato

And mine!

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