Generate Confluence spaces with users

Piotr Dziedziel

Hi,

I need to generate a report/list of all sites in our confluence where we have 3 colums:

 - Space name/link 

 - Key

 - All userid which have access to this space

What is the easiest way to genereate it automatiacally 

Stephen Deutsch

This user macro should do exactly what you asked for:

## @noparams
<table>
 <tr>
  <th>Space</th>
  <th>Key</th>
  <th>Users with access</th>
 </tr>
 #set ( $allUsers = $userAccessor.getUsers() )
 #foreach ( $spaceObject in $spaceManager.getAllSpaces() )
  #if ( $spaceObject.isGlobal() )
   <tr>
    <td><a href="$spaceObject.deepLinkUri">$spaceObject.name</a></td>
    <td><p>$spaceObject.key</p></td>
    <td>
    #foreach ( $user in $allUsers )
     #if ( !$user.isDeactivated() && $permissionHelper.canView($user, $spaceObject) )
      <p> $user.name </p>
     #end
    #end
    </td></tr>
  #end
 #end
</table>

 Note that it might take a long time if you have a lot of users/spaces.