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List all the issues of a project with JIRA Python

Antoine_8zv3vb

Hello all,

All the question is in the title, how to list ALL the issues of a project with JIRA python ?

Actually i've done this code :

def simple_issue(projects):

i = jira.search_issues('issuetype=Bug', maxResults=None)

print(i)

But it list only 50 issues or less. It is due to the fact that issues during the search are shown by pages containing each 50 issues and the python package cannot access to the next pages. Do you know how could i do ?

Or then not to reach has the list of issues but to reach has the list of issuetypes present in the config of the project?

Accepted answers

MattS

block_size = 100
    block_num = 0
    while True:
        start_idx = block_num*block_size
        issues = jira.search_issues(jql, start_idx, block_size)
        if len(issues) == 0:
            # Retrieve issues until there are no more to come
            break
        block_num += 1
        for issue in issues:
            log.info('%s: %s' % (issue.key, issue.fields.summary))

All comments

Petar Petrov _Appfire_

Have you tried using maxResults=sys.maxint (or sys.maxsize if using Python 3)?

Matt Ashfield

Hi,

see args of the function...

search_issues(jql_str, startAt=0, maxResults=50, validate_query=True, fields=None, expand=None, json_result=None)

use startAt and maxResults looping round incrementing StartAt by maxResults

wink

Antoine_8zv3vb

def simple_issue(projects):

i = jira.search_issues("project=project_name", startAt=0, maxResults=50, validate_query=True, fields=None, expand=None, json_result=None)

print(i)

It list 50 issues too ...

Antoine_8zv3vb

import sys ?

Jeff_6i2s3d

That is because you are still specifying maxResults=50, try changing to maxResults=2000

MattS

block_size = 100
    block_num = 0
    while True:
        start_idx = block_num*block_size
        issues = jira.search_issues(jql, start_idx, block_size)
        if len(issues) == 0:
            # Retrieve issues until there are no more to come
            break
        block_num += 1
        for issue in issues:
            log.info('%s: %s' % (issue.key, issue.fields.summary))

Antoine_8zv3vb

it works, thank you !

Behnam Kasmapour Seighalani

Hi all,

I tried this code and got an error for name 'jql'

[SOLVED]

Behnam Kasmapour Seighalani

Then later on when I'm done with this error I get a new one for 'log'

[SOLVED]

Marcello Romani

The server won't return more than a configured number of results at most.

I believe the default is 1000.

Shiva Prasad Rudrappa Hattaraki

import jira.client
from jira.client import JIRA

jira_options={'server': 'https://jira.com'}
jira=JIRA(options=jira_options,basic_auth=('admin','password'))

issues_in_project = jira.search_issues('JQL',startAt=0, maxResults=2000, validate_query=True, fields=None, expand=None, json_result=None)

print (issues_in_project)

This will work for you.

Rushabh_Patel

Hi Shiva,

Using your code it is giving just 100, where my expected answer is 455.

Vivian Young

This is a really old question but I was wondering the same thing. My solution is slightly different from the ones mentioned above.

To remove the default limit of 50 issues, set the limit to something like this:

jira.jql(jql, limit=1000)

Hope this was helpful.

Prod Support

You can set the startAt index to be something else lets say 200 and maxResults to be 300 and it will give issues within that frame. This way you can find others as well and concatenate them. At a time, it gives max 100 issues only.

blueinc

Here's another solution to this old question: I found, in the args of the function, this:

If maxResults evaluates as False, it will try to get all issues in batches.

So, if you just set maxResults=False, it will automagically return all the results. You don't have to guess at a number you 'think' might be higher than the actual number of results or do all of the batching manually.

issues = jira.search_issues(jql_str, maxResults=False)

HTH,

Brian

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