How to list specific JQL column first

Question

I have JQL query: assignee=currentUser() AND type!="Development Sub-task" ORDER BY updatedDate DESC

but i want to display status other than Completed first. Something like this:

assignee=currentUser() AND type!="Development Sub-task" ORDER BY status!=Completed, updatedDate DESC

how to do this?

Andrey Koptelov · Answer

You may try this:

1.
Create custom field "Field_for_sorting" - custom scripted field like "SIL Script Custom Field" (from free addon "Power Custom Fields")
or "Scripted Field" (from not free now "Script Runner for JIRA")

2.
on Edit page of "Field_for_sorting" set "Number Range Searcher" Search Template

3.
on Configure page of "Field_for_sorting" (for SIL Script Custom Field) make SIL Script for your needs.

example for your example:
if( status == "CCCCC") return 1;
return 2;

4.
do reindex all

5.
make your JQL with ORDER BY Field_for_sorting ASC,updated DESC
(you not needed to include Field_for_sorting in columns of filter results, just use in ORDER BY)

6.
be happy)

Thomas Schlegel · Answer

You can't sort status in a way you want to. There is a globally defined order of all the status in Jira.

If you sort your filter result by status, you sort it according to the global sort order defined by your JIRA administrator.

I don't think that you can achieve what you want, your sorting requirements are too complex and are not supported by Jira.

mikmas · Answer

"assignee=currentUser() AND type!="Development Sub-task" ORDER BY status, updatedDate DESC"

I DON'T want to order by status literally, because i'll get something like this:

columns status, updated date

BBBBBB 2017-03-17

BBBBBB 2017-03-16

BBBBBB 2001-03-17

BBBBBB 1939-09-01

CCCCC  2017-03-17

CCCCC  2001-03-17

DDDDD  2017-03-17

DDDDD  2017-03-16

DDDDD  2001-03-17

Admit, that this is useless

I want to display first - for example - CCCCC and AFTER that all others ordered only by updatedDate so something like this: