How to sum up story point of all the subtasks together with the story points of the Parent

Question

Currently I have set up sum-up automation rule for sub-task using:

which works well for the subtasks SPs. So if:

Sub-task 1 = 3

Sub-task2 = 2

The Parent story point = 5 which is fine. But I also want to have the sum of SPs for the parent issue+sub-tasks. In other words, I need the following:

Sub-task 1 = 3

Sub-task2 = 2

Story = 3

The total Story Points of the Story to equal 8

Which query should I use in this case? Using the above mentioned query doesn't work.

Thanks for help

lusine.abrahamyan@disqo.com · Answer

No need for a custom field. The following smart value solves the problem: {{triggerissue.Story Points}} + {{issue.Story Points}}

Bill Sheboy · Answer

Thanks for that information, and...

It would appear there is work for the Story separate from the child Subtasks...which is why I considered that to be other work that is missing a Subtask.

To do what you describe with story points, you would need a separate custom field for the total story points, although none of the built-in functions for reporting will work with that field: velocity, burn charts, etc.

lusine.abrahamyan@disqo.com · Answer

Hi @Bill Sheboy

Nice to meet you.

There are no missing subtasks. And subtasks are aways estimated. Let me clarify:

Assume we have a Story and 2 sub-tasks.

Story has Assignee 1

Sub-task 1 has Assignee 2

Sub-task 2 has Assignee 3

For some logical reasons we also have assignee for the Story. And we have the following estimations:

Sub-task 1 =3

Sub-task 2 = 2

And the Story is separately estimated = 3

If the Story is not separately estimated it get the sum-up of the sub-tasks, i.e. 5 SP, which is fine. The query used is {{subtasks.Story Points.join(" + ")}}

I want to know if there is a query that will add sub-tasks SPs to the Story's SP, ie:

3+2+3=8

In my former Company we used time estimations and when we were estimating separately the Story and the Sub-tasks, we were getting no duplications but the sum of the 3 tickets. That's why I know that it's possible.