Sprint field value REST API

Maarten Cautreels Community Champion Aug 25, 2013

When trying to get the details of an issue through the REST API the response for the Sprint looks something like this:

  • customfield_10007:[
    • "com.atlassian.greenhopper.service.sprint.Sprint@a29f07[rapidViewId=<null>,state=CLOSED,name=NORD - Sprint 42,startDate=2013-07-29T06:47:00.000+02:00,endDate=2013-08-11T20:47:00.000+02:00,completeDate=2013-08-14T15:31:33.157+02:00,id=107]",
    • "com.atlassian.greenhopper.service.sprint.Sprint@769133[rapidViewId=<null>,state=ACTIVE,name=NORD - Sprint 43,startDate=2013-08-14T15:32:47.322+02:00,endDate=2013-08-23T15:32:47.322+02:00,completeDate=<null>,id=117]"
    ],

It looks like toString of the Sprint class which isn't very easy to parse/read with an application. Is their a way to simple get the Sprint Name or id returned through the REST API. It's necessary to be able to retrieve the Sprint value in an internal tool for our QA Team (Spira Test).

On the other side, using toString in the REST API output doesn't seem like a good idea to me ...

Thanks,

Maarten

7 answers

1 accepted

2 votes
Answer accepted

I was having the same issue for a small tool I was developing in which I needed the sprint name. Since I was using Jackson to unmarshal my JIRA response, I ended up writing a custom deserializer: 

import com.fasterxml.jackson.core.JsonParser;
import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.core.type.TypeReference;
import com.fasterxml.jackson.databind.DeserializationContext;
import com.fasterxml.jackson.databind.JsonDeserializer;

import java.io.IOException;
import java.util.Collection;
import java.util.HashMap;
import java.util.Map;
import java.util.function.Function;

import static java.util.stream.Collectors.toList;

public class SprintNamesExtractingDeserializer extends JsonDeserializer<Collection> {

private static final String OPEN_ARRAY_CHARACTER = "\\[";
private static final String CLOSE_ARRAY_CHARACTER = "]";
private static final String COMMA = ",";
private static final String EQUALS_SIGN = "=";
private static final String NAME_PROPERTY = "name";

public SprintNamesExtractingDeserializer() {
}

@Override
public Collection deserialize(final JsonParser jsonParser, final DeserializationContext deserializationContext) throws IOException, JsonProcessingException {
TypeReference<Collection<String>> typedCollection = new TypeReference<Collection<String>>() {
};
Collection<String> sprints = jsonParser.readValueAs(typedCollection);
return sprints.stream()
.map(extractSprintName())
.collect(toList());
}

private Function<String, String> extractSprintName() {
return sprintString -> {
String result = sprintString.split(OPEN_ARRAY_CHARACTER, 2)[1];
Map<String, String> sprintProperties = extractSprintProperties(result);

return sprintProperties.getOrDefault(NAME_PROPERTY, null);
};
}

private Map<String, String> extractSprintProperties(String result) {
int lastArrayClosure = result.lastIndexOf(CLOSE_ARRAY_CHARACTER);
result = result.substring(0, lastArrayClosure);
String[] propertiesArray = result.split(COMMA);
HashMap<String, String> properties = new HashMap<>();
for (String property: propertiesArray) {
String[] keyValueArray = property.split(EQUALS_SIGN);
if (keyValueArray.length == 1) {
properties.put(keyValueArray[0], null);
} else if (keyValueArray.length == 2) {
properties.put(keyValueArray[0], keyValueArray[1]);
}
// Else it's not a valid property
}
return properties;
}

}

Which can be used as: 

@JsonProperty("customfield_10400")
@JsonDeserialize(using = SprintNamesExtractingDeserializer.class, as=Collection.class)
public abstract Collection<String> getSprintNames();

 I'm not particularly proud of this solution, but it does the trick. 

@Stef Klaassen, thank you! I used your method extractSprintProperties to get readable data from sprint string retrieved from the field.

No idea why would API return JSONArray with no way to cleanly cast it to array of sprints. I also need to get the state out of sprint and mark active one.

2 votes
Maarten Cautreels Community Champion Sep 11, 2013

No Answer has been found :-(

Can you please give me the rest call url to fetch the data which you have found havent even have that url to fetch that data for me . thanks!

Any idea of one jar containing the mentioned class com.atlassian.greenhopper.service.sprint.Sprint
I assume the response can be parsed something like the following:

Field field = issue.getFieldByName("Sprint");
JSONArray fieldValue = (JSONArray) field.getValue();
com.atlassian.greenhopper.service.sprint.Sprint sprint = (Sprint) fieldValue.get(0);

I just can't find the particular class/jar.

Found it, but it looks too big to include, I think I'll go with parsing it as a String.

Jar info can be found at https://www.versioneye.com/java/com.atlassian.jira.plugins:jira-greenhopper-plugin/6.2

0 votes
Timothy Chin Community Champion Aug 25, 2013

It's not hard to parse that. The toString returns a JSON representation of that object. You just need to convert that String into a JSON object.

Maarten Cautreels Community Champion Sep 01, 2013

It's far from JSON ...

JSON would be something like this:

{
	rapidViewId: 1,
	state: "Closed",
	name: "NORD - Sprint 42",
	...
}

[ignore]Double-post because of spam filter not letting through my code example.[/ignore] 

Haven't found a great way, but this works pretty well.  Using that Java class seems like it would match best, but honestly we shouldn't have to do this sort of parsing for a JSON REST API.

You can pipe that field through the `jq` utility this way to turn that rubbish Java serialization into desired JSON:

match("[\\\\w.]+?@\\\\w+?\\\\[(.*?)\\\\]").captures[0].string | split(",") | map(split("=") | {"key": .[0], "value": .[1]}) | from_entries

 

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