Is there a Property Name/Property Value pair I could employ on the workflow to prevent a subtask from being created against a specific parent issue type. If not obvious, the goal is to prevent someone from creating a subtask on an Epic issue type.
I currently use a custom property to prevent work logs from being generated against parent issues so I'm seeking something similar.
After thinking about this for a while, I came up with a cheap, simple solution...
My Epic issue type uses a distinct workflow that has it's own set of statuses, so in order to allow a subtask to be created from an Epic, from all of my subtask workflows, I simply force the status of the parent to be in one of the statuses not afforded to the Epic issue type. I'll explain in practice below:
Hi Paul, I came across your post which looks like the solution to the problem that I have.
My need is that I want to prevent my users from creating subtasks directly in Epics. They should only be able to link regular issues with Epics.
Although generally I get the idea of your solution, however could you give me some example or direct me to Atlassian documentation where it is explained more about "I only allow creation of a subtask if the parent's status is not in those defined in #1 above"
Thanks in advance.
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Bogdan, from the Create step of each subtask workflow in your instance, use a Validator like this to disallow the creation of the subtask if the parent is not in one of these other statuses. In my case, I use a set of statuses for my Epic that are not used by any other issue type so that is why my proposed solution works. Notice below it specifies statuses not used by the Epic.
The parent issue of current issue must be in one of the following statuses: Open, Engineering, QA, etc...etc...
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
No options on onDemand AFAIK. Haven't seeen any workflow property for this.
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.