Suppose we have 4 user stories(A,B,C,D) inside an epic. Now while logging Bug I linked them to respective user stories. So Now it will looks like
A: Bug-1,Bug-2
B: Bug-3, Bug-4
C: Bug-5,Bug-6
D: Bug-7
I want to create a query which will display me bugs linked to a particular Story. For example if i ran my query for user story A, It should give me Bug-1,Bug-2 in result
Hello,
You can use out of the box function
linkedIssues(issueKey,CaseSensitiveLinkType)
In your case it would look like this
issue in linkedIssues(STORY-123,"is blocked by")
Thanks, Alexey!
issue in linkedIssues(STORY-123,"relates to") AND issuetype=Bug
This query fulfills my purpose. Thanks again :)
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