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Distinct user from multi-user custom field in Jira Automation

Hi all,

I am creating an automation that will send emails to all interested users when a version is released. There is a custom issue field "Notify on Release" that can contain multiple users per issue who should be notified.

I fetched all issues where this custom field is not empty and now need to get a list of distinct users to be notified. If my custom field contained only a single user, I could simply assign this to a new variable: `{{lookupIssues.Notify on Release.distinct}}`, but since my custom field can contain multiple users this will not work.

Example:

  • Issue 1 - Notify on Release: User A, User B
  • Issue 2 - Notify on Release: User A
  • Issue 3 - Notify on Release: User A

This would result in the following list: (User A, User B), User A.

Is there a way to combine all elements in a single list first and then run distinct on them?

Thank you in advance!

1 answer

1 vote
Alex Koxaras Community Leader Sep 07, 2022

Hi @Cornelius Schiffer 

Can you try to create a new variable after that lookupissues and assign the value of {{lookupIssues.Notify on Release.distinct}}. Then call the distinct method on the new variable. Log it and see what this yields.

Hi Alex, 

thank you for the answer!

I tried it like this:

Bildschirmfoto 2022-09-07 um 12.26.57.png

The first log shows the users, the second only the static text. My new variable "distinctUsersToNotify" seems to be empty.

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